- #1
yoyomaboy
- 3
- 0
Physics Problem using constant speed.
hey guys, here the problem.
Two ferryboat each traveling at different constant speed start at the same instant from opposite sides of the Hudson River, one going from New York City to Jersey City and the other from Jersey City to New York City. They pass one another at a point 720 yard from New York City shore. After arriving at their respective destinations, each boat spends precisely 10 minutes at the opposite shore to change passengers before switching directions. On the return trip, the two boats meet at a point 400 yards from the Jersey shore.
What is the width of the river?
I drew out diagrams of the river and added in the all the nessasary details. I'm using X=Xi+Vit+1/2at^2. For boat A, solved and got 720=Viat (Via is the initial speed of boat A) and for boat B I solved and got x-720=Vibt (Vib is the intial speed of boat B) (I'm using x as the total width of the river). There is no acceleration, so the 1/2at^2 will cancel out.
For the second time they pass each other i got the equations
Boat A=400=Viat
Boat B=x-400=Vibt
I was thinking that you have to set these equations equal to one another and some how get a ratio, but, these equations are getting me nowhere. Any tips to get me started in the right direction from here will be greatly appreciated
hey guys, here the problem.
Two ferryboat each traveling at different constant speed start at the same instant from opposite sides of the Hudson River, one going from New York City to Jersey City and the other from Jersey City to New York City. They pass one another at a point 720 yard from New York City shore. After arriving at their respective destinations, each boat spends precisely 10 minutes at the opposite shore to change passengers before switching directions. On the return trip, the two boats meet at a point 400 yards from the Jersey shore.
What is the width of the river?
I drew out diagrams of the river and added in the all the nessasary details. I'm using X=Xi+Vit+1/2at^2. For boat A, solved and got 720=Viat (Via is the initial speed of boat A) and for boat B I solved and got x-720=Vibt (Vib is the intial speed of boat B) (I'm using x as the total width of the river). There is no acceleration, so the 1/2at^2 will cancel out.
For the second time they pass each other i got the equations
Boat A=400=Viat
Boat B=x-400=Vibt
I was thinking that you have to set these equations equal to one another and some how get a ratio, but, these equations are getting me nowhere. Any tips to get me started in the right direction from here will be greatly appreciated
Last edited: