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Equation of the line for a second order decay

 
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Jun26-12, 03:42 PM   #1
 

Equation of the line for a second order decay


What is it?!! I have tried plotting dummy data showing y values halving as x values double and no simple type of equation results (ie exponential, power, polynomial etc) - is this true? I thought such a standard function would be a simple one!
 
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Jun26-12, 03:46 PM   #2
 
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Yes, it is pretty simple. You are talking about a simple "inverse" proportion: y= C/x or xy= C. When x doubles, that is, x becomes 2x, y must halve in order that the product be constant: (2x)(y/2)= xy= C. If you want to think of that as a "power" it is [itex]y= Cx^{-1}[/itex]
 
Jun26-12, 03:49 PM   #3
 
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Quote by Miffymycat View Post
What is it?!! I have tried plotting dummy data showing y values halving as x values double and no simple type of equation results (ie exponential, power, polynomial etc) - is this true? I thought such a standard function would be a simple one!
What about y = A/x ?


EDIT -- Oops, beaten out by Halls again!
 
Jun26-12, 04:10 PM   #4
 

Equation of the line for a second order decay


Sorry guys _ I meant that the x value interval doubles eg y = 100, 50, 25, 12.5; x = 0, 10, 30, 70 ie a second order decay where x represents elapsed time ie the half-life of the decay is doubling. Any ideas?
 
Jun26-12, 04:49 PM   #5
 
y=1000/(x+10)
You can express both x and y as functions of powers of 2 (2^n where n=0,1,2,...).
Eliminate 2^n to find y as function of x.
 
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