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Hi, a small question about the LSZ reduction formula, as treated in Srednicki's QFT book (chapter 5).
He argues that in a QFT in a scalar theory with interactions you would like that
[tex]
<0|\phi(x)|0> = <0|\phi(0)|0> = 0
[/tex]
and
[tex]
<p|\phi(0)|0> = 1
[/tex]
For the first he argues that were this NOT the case, then the creation operators [itex] a^\dagger (\pm\infty)[/itex] would create a linear combination of a single particle state and the ground state.
For the second he argues that the second condition accounts for the fact that the creation operators create a correctly normalized one-particle state.
How does one see these two statements? Thanks in forward! :)
He argues that in a QFT in a scalar theory with interactions you would like that
[tex]
<0|\phi(x)|0> = <0|\phi(0)|0> = 0
[/tex]
and
[tex]
<p|\phi(0)|0> = 1
[/tex]
For the first he argues that were this NOT the case, then the creation operators [itex] a^\dagger (\pm\infty)[/itex] would create a linear combination of a single particle state and the ground state.
For the second he argues that the second condition accounts for the fact that the creation operators create a correctly normalized one-particle state.
How does one see these two statements? Thanks in forward! :)