How Does Pressure Affect Water Density in the Mariana Trench?

In summary: And the V2 is 1m3, so you can calculate the density at the bottom.In summary, the deepest point in the ocean is in the Mariana Trench, about 11 km deep, and has a pressure of 1.13 x 108 N/m2. The density of water at the surface is 1.03 x 103 kg/m3, and using the equation P=B(ΔV/V), we can determine the change in volume of 1.00 m3 of water carried from the surface to the bottom of the Pacific. The density at the bottom can be calculated using the formula q1*V1 = q2*V2, where q is density and V is volume.
  • #1
mandy9008
127
1

Homework Statement


The deepest point in the ocean is in the Mariana Trench, about 11 km deep. The pressure at that point is huge, about 1.13 x108 N/m2.
(a) The deepest point in the ocean is in the Mariana Trench, about 11 km deep. The pressure at that point is huge, about 1.13 x108 N/m2.
(b) The density of water at the surface is 1.03 x103 kg/m3. Find its density at the bottom.


Homework Equations


P=B(ΔV/V)


The Attempt at a Solution


a. 1.13 x108 N/m2 = -(2.15 x109 Pa)(ΔV/(1.00 m3))
ΔV = -0.053 m3
b. Since water is not compressible, shouldn't the density be the same at the bottom of the ocean as the top?
 
Physics news on Phys.org
  • #2
Well, everything is compressible, only the force required to compress it is different for each material. I don't know what your a. question was, since it seems you copied it wrong, but I see you calculated some sort of deltaV. If the volume changed, shouldn't the density have also changed?

http://hyperphysics.phy-astr.gsu.edu/hbase/permot3.html
 
  • #3
yes, i did copy part a wrong. the question for part a was: (a) Calculate the change in volume of 1.00 m3 of water carried from the surface to the bottom of the Pacific.
so, if the density is different, how do i determine the change?
 
  • #4
Well I'm not sure, but you should be able to calculate the weight of 1m3 water (don't know the density of sea-water...), and after you carried it down, the mass is still the same, so because m = qV, where q is density, you could say q1*V1 = q2*V2, and only q2 is unknown.
 
  • #5
The pressure at the bottom of the Mariana Trench is indeed huge, but the bulk modulus and density of water remain constant regardless of pressure. This is because water molecules are already tightly packed and cannot be compressed further. Therefore, the density of water at the bottom of the ocean would still be 1.03 x103 kg/m3, the same as at the surface. The pressure at the bottom of the ocean may be immense, but it does not affect the density of water.
 

1. What is bulk modulus?

Bulk modulus is a measure of the resistance of a material to compressibility under uniform pressure. It is also referred to as the compressibility modulus or the volume modulus.

2. How is bulk modulus calculated?

Bulk modulus is calculated by dividing the change in pressure by the corresponding change in volume for a given material. It is represented by the symbol K and is measured in units of pressure (usually Pascal or GigaPascal).

3. What factors affect the bulk modulus of a material?

The bulk modulus of a material is affected by its density and elasticity. Materials with higher density and lower elasticity have a higher bulk modulus, while materials with lower density and higher elasticity have a lower bulk modulus.

4. What is the relationship between bulk modulus and density?

The bulk modulus and density of a material are directly related. As the density of a material increases, its bulk modulus also increases. This means that denser materials are more resistant to compression under uniform pressure.

5. How is bulk modulus used in practical applications?

Bulk modulus is an important property in engineering and materials science. It is used to determine the compressibility and stiffness of materials, and is essential in the design and construction of structures such as buildings, bridges, and airplanes. It is also used in the study of fluid mechanics and acoustic properties of materials.

Similar threads

  • Introductory Physics Homework Help
Replies
1
Views
714
Replies
3
Views
8K
  • Introductory Physics Homework Help
Replies
13
Views
14K
  • Introductory Physics Homework Help
Replies
2
Views
7K
  • Introductory Physics Homework Help
Replies
1
Views
8K
  • Introductory Physics Homework Help
Replies
7
Views
12K
  • Introductory Physics Homework Help
Replies
4
Views
9K
  • Introductory Physics Homework Help
Replies
2
Views
11K
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Chemistry
Replies
1
Views
2K
Back
Top