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Ricci Tensor of FRW

 
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Mar31-12, 02:44 PM   #18
 

Ricci Tensor of FRW


No, you sum over ALL the indices!
 
Mar31-12, 02:47 PM   #19
 
Quote by clamtrox View Post
No, you sum over ALL the indices!
i.e t= μ and t = [itex]\nu[/itex]

How the does Ricci tensor equation looks like then?

[itex] R_{rr} = R^{\mu}_{r\mu r} + R^{\nu}_{r\nu r} [/itex]

Since [itex] R^{\mu}_{r\mu r} = a\ddot{a}[/itex]

and [itex] R^{\nu}_{r\nu r} = a\ddot{a}[/itex]

[itex] R_{rr} = 2 a\ddot{a}[/itex]

that's not correct. I don't know I am getting confused. I am not seeing how we get [itex]\dot{a}[/itex]2
 
Mar31-12, 03:07 PM   #20
 
Quote by psimeson View Post
i.e t= μ and t = [itex]\nu[/itex]

How the does Ricci tensor equation looks like then?

[itex] R_{rr} = R^{\mu}_{r\mu r} + R^{\nu}_{r\nu r} [/itex]

Since [itex] R^{\mu}_{r\mu r} = a\ddot{a}[/itex]

and [itex] R^{\nu}_{r\nu r} = a\ddot{a}[/itex]

[itex] R_{rr} = 2 a\ddot{a}[/itex]

that's not correct. I don't know I am getting confused. I am not seeing how we get [itex]\dot{a}[/itex]2
no no no, Ricci tensor is the trace of Riemann tensor, so [itex] R^{\mu}_{r\mu r} = R^{t}_{rtr} +R^{r}_{rrr} + R^{\theta}_{r \theta r} + R^{\phi}_{r \phi r} [/itex]
 
Mar31-12, 03:19 PM   #21
 
Quote by clamtrox View Post
no no no, Ricci tensor is the trace of Riemann tensor, so [itex] R^{\mu}_{r\mu r} = R^{t}_{rtr} +R^{r}_{rrr} + R^{\theta}_{r \theta r} + R^{\phi}_{r \phi r} [/itex]
So that means, for x, y and z, I have:

[itex]R^{\mu}_{x\mu x} = R^{t}_{xtx} +R^{x}_{xxx} + R^{y}_{x y x} + R^{z}_{xzx}[/itex] right?

But the second term is zero and 3rd and 4th term does not have time in it so I will not "a" contribution from them
 
Mar31-12, 03:21 PM   #22
 
I think I got it.. Thanks a lot
 
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