Latent heat of Fusion Lab

In summary: The change in temperature is +, going from -23 to zero.And please don't say "NRG." Use "Q" which stands for "heat."Q=mLa) (.45kg) (4.2x10^3 J/kg) (-23'C)=-4.3x10^6 Jb) (.45kg) (3.3x10^5 J/kg) = 1.5x10^5 Jc) (.45kg) (3.3x10^5 J/kg) (100'C)
  • #1
srose9625
21
0
A student takes 0.45kg of ice. The ice is initally at -23'C. She heats the sample in an oven until the temp is 134'C.
a). What is the NRG needed to heat the ice to its melting point?
b). What is the NRG needed to change the solid ice into liquid water?
c). What is the NRG needed to heat the liquid water to its boiling point?
d). What is the NRG needed to change the liquid water to steam?
e). What is the NRG needed to heat the steam to 134'C?
f). Draw a graph with the temp of the sample in Kelvin on y axis, and NRG absorbed in Joules by the sample on the x axis.


Equations of use:
Q=mc(change in T)
Q=mL

a) (.45kg) (4.2x10^3 J/kg) (-23'C)=-4.3x10^6 J
b) (.45kg) (3.3x10^5 J/kg) = 1.5x10^5 J
c) (.45kg) (3.3x10^5 J/kg) (134'C) = 1.2x10^7 J
d) (.45kg) (2.3x10^6 J/kg) = 1.0x10^6 J
e) (.45kg) (2.3x10^6 J/kg) (134'C) = 1.4x10^8 J
f) I have ice drawn in a straight/horizontal line, then water drawn in a linear line followed by a straight/horizontal line, then steam in a linear line, then boiling in a straight/horizontal line.
 
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  • #2
a) b) and d) are correct but, why is a) a negative answer? The change in temperature is +, going from -23 to zero.

and c). Do you know the temperature at which liquid water will boil?

And please don't say "NRG." Use "Q" which stands for "heat."
 
  • #3
a). (.45kg) (4.2x10^3 J/kg) (23'C) = 4.3x10^6 J
Is that still right?

c). (.45kg) (3.3x10^5 J/kg) (100'C) = 1.2x10^7 J
I am guessing that water boils at 100'C. Would that be the right answer?

e). (.45kg) (3.3x10^5 J/kg) (134'C) = 1.2x10^7 J
OR
(.45kg) (2.3x10^6 J/kg) (134'C) = 1.4x10^8 J

f). I have ice drawn in a straight/horizontal line, then water drawn in a linear line followed by a straight/horizontal line, then steam in a linear line, then boiling in a straight/horizontal line.
 

1. What is the purpose of the Latent Heat of Fusion Lab?

The purpose of the Latent Heat of Fusion Lab is to measure the amount of energy required to melt a substance and determine its latent heat of fusion.

2. What materials are needed for the Latent Heat of Fusion Lab?

The materials needed for the Latent Heat of Fusion Lab include a calorimeter, water, a thermometer, a heating source, and the substance being tested for its latent heat of fusion.

3. How is the latent heat of fusion calculated in this lab?

The latent heat of fusion is calculated by measuring the temperature change of the substance as it melts and using the formula Q = m x L, where Q is the amount of heat energy absorbed, m is the mass of the substance, and L is the latent heat of fusion.

4. What is the relationship between latent heat of fusion and melting point?

The latent heat of fusion and melting point are directly proportional. As the melting point of a substance increases, so does its latent heat of fusion. This is because substances with higher melting points require more energy to break their intermolecular bonds and change from solid to liquid state.

5. How is the latent heat of fusion important in various industries?

The latent heat of fusion is important in industries such as food processing, pharmaceuticals, and materials manufacturing. It is used to determine the amount of energy needed to melt substances for various purposes, such as creating products with specific textures and melting ingredients for mixing and blending.

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