- #1
predentalgirl1
- 67
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Hello. Just need this answer checked. Thanks.
If we can reasonably treat acetone vapor as an ideal gas at the Tboil =70° C and we approximate the volume of a Hickman still as ~25mL then how many moles of acetone are in the vapor phase inside the still? (PV=nRT) (R=0.0821 L*atm/mol*K) (Get conversion of P & T in right form.)
Answer:-
T= 70+273=343K
P=0.736/760=9.68x10-4atm
R=0.0821 L*atm/mol*K
V= 25x10-3L
n=no.of moles = PV/RT= 9.68x10-4atm x 25x10-3L /(0.0821 L*atm/mol*K x 343K)
= 8.59x10-7
If we can reasonably treat acetone vapor as an ideal gas at the Tboil =70° C and we approximate the volume of a Hickman still as ~25mL then how many moles of acetone are in the vapor phase inside the still? (PV=nRT) (R=0.0821 L*atm/mol*K) (Get conversion of P & T in right form.)
Answer:-
T= 70+273=343K
P=0.736/760=9.68x10-4atm
R=0.0821 L*atm/mol*K
V= 25x10-3L
n=no.of moles = PV/RT= 9.68x10-4atm x 25x10-3L /(0.0821 L*atm/mol*K x 343K)
= 8.59x10-7