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rissa_rue13
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Homework Statement
There is an equilateral triangle with one point charge at each vertex. The point charges have charges of +Q, +2Q, and -4Q. The length of one side of the triangle is L. Determine an expression in simplest form for the voltage at a point halfway between the +Q and +2Q point charges.
Homework Equations
V=kQ/r
Vnet=V1+V2+V3
The Attempt at a Solution
Going off of Vnet=V1+V2+V3:
Vnet= (kQ/r) + (k2Q/r) - (k4Q/r)
I think once substituting the values for L in place of r, you get:
Vnet= (kQ/(L/2)) + (k2Q/(L/2)) - (k4Q/Lcos30)
Am I heading in the right direction?