
#1
Dec2413, 12:19 PM

P: 35

Hi....!
I was trying to understand the meaning of the binary Energy (E_{b}) .. For example : Imagine we have two cores ... 1 from an X atom and 1 from an Y atom which have the same A and X has bigger E_{b} than Y ... while Y is the stable core for that exact A ... That means Because energy is never lost E_{b} + E_{Y} = E_{p} + E_{n} ⇔ .... ⇔ E_{b} = ( ZM_{p} + NM_{n}  M_{Y} )c^{2} But what i cant understand is the following Why isnt X more stable as it has bigger binary energy therefore the same number of protons and netrons are hold by bigger power ? HOWEVER if we look at the opposite way Why isnt any core with smaller binary energy and same A than X stablier because its stableness would require less energy ... But our researches have shown that both above are not true ... but why ? 



#2
Dec2413, 06:48 PM

Mentor
P: 10,853

What is "binary energy"? Do you mean "binding energy"?
An atom K can decay into another atom L of the same nucleon number if L has a larger binding energy, the opposite is not possible neglecting electron capture. 



#3
Dec2513, 08:20 AM

P: 35

I am wondering about which cell is stablier K or L (fro your example ) .. and why ... 



#4
Dec2513, 10:38 AM

Mentor
P: 10,853

Need help with stableunstable cores(cells)
If both are unstable, there is no general rule for their lifetimes, it depends on too many other factors (like nuclear spin, odd/even proton/neutron numbers and so on). The setup you described in post 1 (instable atom with larger binding energy decaying to stable atom with smaller binding energy) is not possible. Again, neglecting electron capture.



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