Need help with stable-unstable cores(cells)


by radioactive8
Tags: corescells, stableunstable
radioactive8
radioactive8 is offline
#1
Dec24-13, 12:19 PM
P: 35
Hi....!
I was trying to understand the meaning of the binary Energy (Eb) ..
For example :
Imagine we have two cores ... 1 from an X atom and 1 from an Y atom which have the same A and X has bigger Eb than Y ... while Y is the stable core for that exact A ...
That means
Because energy is never lost
Eb + EY = Ep + En ⇔ .... ⇔

Eb = ( ZMp + NMn - MY )c2

But what i cant understand is the following

Why isnt X more stable as it has bigger binary energy therefore the same number of protons and netrons are hold by bigger power ?

HOWEVER if we look at the opposite way
Why isnt any core with smaller binary energy and same A than X stablier because its stableness would require less energy ...

But our researches have shown that both above are not true ... but why ?
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mfb
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#2
Dec24-13, 06:48 PM
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P: 10,853
What is "binary energy"? Do you mean "binding energy"?

An atom K can decay into another atom L of the same nucleon number if L has a larger binding energy, the opposite is not possible neglecting electron capture.
radioactive8
radioactive8 is offline
#3
Dec25-13, 08:20 AM
P: 35
What is "binary energy"? Do you mean "binding energy"?
Yes

An atom K can decay into another atom L of the same nucleon number if L has a larger binding energy, the opposite is not possible neglecting electron capture.
This doent answer my question .....
I am wondering about which cell is stablier K or L (fro your example ) .. and why ...

mfb
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#4
Dec25-13, 10:38 AM
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P: 10,853

Need help with stable-unstable cores(cells)


If both are unstable, there is no general rule for their lifetimes, it depends on too many other factors (like nuclear spin, odd/even proton/neutron numbers and so on). The setup you described in post 1 (instable atom with larger binding energy decaying to stable atom with smaller binding energy) is not possible. Again, neglecting electron capture.


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