- #1
robert25pl
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Electric field due to a cylindrical charge distribution using Gauss' law.
Charge is distributed with density [tex]\rho_{0}e^{-r^{2}}[/tex] C/m^3 in cylindrical region r < 1. Find D (displacement flux density vector) everywhere.
I did used this equation
[tex]\int_{s}D\cdot\,dS=\int_{V}\rho\*d\upsilon[/tex]
Since this is a cylindrical charge distribiution I used Gaussian surface in the shape of a cylinder.
[tex]\int_{s}D\cdot\,dS=\rho\*l[/tex]
So if I understand good the D=0 inside cylinder. therefore r>R is valid.
The surface area is [tex]2\pi\*rL[/tex].
I'm having a problem to set up the the equation or I'm doing everything wrong?
Thanks for any help and recommendation.
Charge is distributed with density [tex]\rho_{0}e^{-r^{2}}[/tex] C/m^3 in cylindrical region r < 1. Find D (displacement flux density vector) everywhere.
I did used this equation
[tex]\int_{s}D\cdot\,dS=\int_{V}\rho\*d\upsilon[/tex]
Since this is a cylindrical charge distribiution I used Gaussian surface in the shape of a cylinder.
[tex]\int_{s}D\cdot\,dS=\rho\*l[/tex]
So if I understand good the D=0 inside cylinder. therefore r>R is valid.
The surface area is [tex]2\pi\*rL[/tex].
I'm having a problem to set up the the equation or I'm doing everything wrong?
Thanks for any help and recommendation.