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Glashow-Weinberg-Salam problem with mass terms

by Karozo
Tags: glashowweinbergsalam, mass, terms
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Karozo
#1
Aug13-14, 06:11 PM
P: 4
At the end of spontaneous symmetry breaking I get these mass terms:

[itex]W_{\mu}^{\pm}=\frac{1}{\sqrt{2}}\bigl(W_{\mu}^{1} \mp W_{\mu}^{2} \bigr )[/itex]

[itex]\mathcal{L}_{mass}=\frac{1}{2} g^2 \frac{v^2}{4} W_{\mu}^{+}{W^{\mu}}^{-} + \frac{1}{2} g^2 \frac{v^2}{4} W_{\mu}^{-}{W^{\mu}}^{+} [/itex]

So I have [itex] M_{W^+}=g \frac{v}{2} \quad M_{W^-}=g \frac{v}{2} [/itex]

Is it right? Or there are too many terms and it is enough:

[itex]\mathcal{L}_{mass}= \frac{1}{2} g^2 \frac{v^2}{4} W_{\mu}^{-}{W^{\mu}}^{+} [/itex]
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ChrisVer
#2
Aug15-14, 01:37 PM
P: 1,041
The mass terms seem right.
You can always write it as the last + h.c. which is your 2nd term
Orodruin
#3
Aug15-14, 04:16 PM
P: 680
Well, the W fields commute so there really is no point in writing it as two terms or with hc., just add a 2.


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