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Locally Compact Hausdorff Space is Regular |
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| Jan10-13, 08:00 AM | #1 |
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Locally Compact Hausdorff Space is Regular
So, I'm working a bit through munkres and I came across this problem
Show that every locally compact Hausdorff space is regular. So, I think I've solved it, but there is something confusing me. I initially said that if [itex]X[/itex] is locally compact Hausdorff, it has a 1-point compactification, [itex]Y[/itex], which is compact Hausdorff. Then, by some theorem in Munkres (32.3), every compact Hausdorff space is normal. Then again by Munkres, (page 195), a normal space is regular, and a subspace of a regular space is regular, so that [itex]X[/itex] is regular. Now, my confusion here is that Munkres defines normal and regular only when 1-point sets are closed. It is not entirely clear to me that this is true for a compact Hausdorff space. Is it? Because if so, then I see that normal implies regular and the proof is done. Even without this though, I can see that any compact Hausdorff space is regular purely from the definition of compact and Hausdorff (at least for the definition of regular not using the fact that 1-point sets are closed), and so a subspace of [itex]Y[/itex], namely [itex]X[/itex], must be regular. |
| Jan10-13, 09:07 AM | #2 |
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Singletons are always closed in a Hausdorff space. Try to prove it if you haven't.
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| Jan11-13, 06:48 AM | #3 |
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O, that was dumb.
In general though, do people reguire that normal spaces have 1 point closed sets so that normal implies regularity? It seems that that is what Munkres does. |
| Jan11-13, 09:48 AM | #4 |
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Locally Compact Hausdorff Space is Regular |
| Jan11-13, 03:41 PM | #5 |
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I wonder then, which of his theorems depend on it, since its not always clear. I think most of his comparisons between regular spaces and normal spaces include the use of a Hausdorff space (well-ordered sets in the order topology, compact Hausdorff sets, metrizable spaces), so it all seems consistent, but I don't know for sure.
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