Proofing the derivatives of e^x from the limit approach

Gloyn

Hetware, maybe it's lame question, but where did the last line come from? I mean, the thing

1=e^x d(e^x)/dx

lurflurf

^
1=x'=(log(e^x))'=(e^-x)(e^x)'

Gloyn

Thanks, don't know how I could miss that :).

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Gloyn	Proofing the derivatives of e^x from the limit approach Hetware, maybe it's lame question, but where did the last line come from? I mean, the thing 1=e^x d(e^x)/dx

lurflurf Recognitions: Homework Help	^ 1=x'=(log(e^x))'=(e^-x)(e^x)'