Reflection Grating Homework Solution

In summary, the conversation is about a problem involving a grating equation and finding the angle of incidence for first order maxima. The equation used by the person is not correct for the given conditions, and the correct equation includes the angle of incidence.
  • #1
VVill
2
0

Homework Statement


http://img244.imageshack.us/img244/6852/phys24xy.png [Broken]


Homework Equations


d=1/N d*sin(theta)=m*(lambda)


The Attempt at a Solution


d=1/1970
d=.0005076

.0005076*sin(theta)=2*600e-9

sin(theta)=.0000012/.0005076

arcsin(.002364)=.135º

*sigh*
 
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  • #2
One thing I see is that when you found d you didn't convert from cm to m, so you have inconsistent units in your equation.
 
  • #3
d=.0005076cm = .000005076m

.000005076*sin(theta)=2*600e-9

sin(theta)=.0000012/.000005076

arcsin(.2364)=13.7º

Anything else I'm missing, because the answer is not 13.7º?
 
  • #4
Why do you have m=2? If it is first order I would think it would be m=1.
 
  • #5
Are you sure you are using the right equation? I think the grating equation you are using is not quite right for the conditions of your problem. The one you are using is a special case where the angle of incidence is normal to the grating. You need to include the angle of incidence in your equation. So your equation would be
d*(sin(theta(m)) - sin(theta(inc))) =m*lamda. where m = ±1 for first order maxima. Anyway see if that helps.
 

1. What is a reflection grating?

A reflection grating is a device used in optical instruments to disperse light into its component wavelengths. It consists of a flat surface with closely spaced parallel grooves that act as a diffraction grating.

2. How does a reflection grating work?

When a beam of light hits the surface of a reflection grating, it is diffracted into its component wavelengths. This is due to the grooves on the surface acting as a series of parallel slits, causing the light to interfere with itself and creating a spectrum.

3. What is the difference between a reflection grating and a transmission grating?

A reflection grating works by reflecting light off its surface, while a transmission grating works by allowing light to pass through its material. Reflection gratings are typically used for higher resolution and are more efficient, while transmission gratings are easier to manufacture and can be used for wider spectral ranges.

4. How is a reflection grating used in spectroscopy?

In spectroscopy, a reflection grating is used to disperse light into its component wavelengths, creating a spectrum that can be analyzed to identify the chemical composition of a substance. The spacing of the grooves on the grating determines the resolution of the spectrum.

5. What are some common applications of reflection gratings?

Reflection gratings are used in a variety of scientific and industrial applications, including spectroscopy, laser systems, and optical communication systems. They are also used in astronomical telescopes to analyze the light emitted by celestial objects.

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