Pressure, Density, and Atmospheric Pressure

In summary, the absolute pressure at a depth of 15 m below the sea surface is 251.45 kPa. This is found by using the formula P = p*d*g*h + P_atm, where p is the density of seawater, g is the acceleration due to gravity, h is the depth (15m in this case), and P_atm is the atmospheric pressure. Plugging in the given values, we get P = (1.03 g/cm3)(10 m/s2)(15 m) + 101 kPa = 251.45 kPa.
  • #1
kallisti
2
0

Homework Statement



What is the absolute (total) pressure at the depth of 15 m below the surface of the sea. Assume density of seawater is 1.03 g/cm3 and g=10 m/s2. Give answer in kPa. Use atmospheric pressure is 101 kPa.


Homework Equations



P = F/A
P1V1=P2V2


The Attempt at a Solution



i don't know how to solve it because neither of the formulae my teacher gave me have atmostpheric pressure or density and the problem doesn't have volume please help!
 
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  • #2
Pressure in this case doesn't depend on volume, it just depends on gravity, density and the height of the fluid column above you. You've probably seen the equation before- p=d*g*h.

The total, then, is just that plus atmospheric pressure.
 
  • #3


As a scientist, it is important to understand and apply the relevant equations and principles to solve problems. In this case, we can use the equation P = ρgh, where P is the absolute pressure, ρ is the density of the fluid (seawater in this case), g is the acceleration due to gravity, and h is the depth. We can rearrange this equation to solve for P:

P = ρgh = (1.03 g/cm3)(10 m/s2)(15 m) = 154.5 kPa

However, this answer only gives us the gauge pressure, which is the pressure above atmospheric pressure. To find the absolute pressure, we need to add the atmospheric pressure to this value:

Pabsolute = P + Patm = 154.5 kPa + 101 kPa = 255.5 kPa

Therefore, the total absolute pressure at a depth of 15 m below the surface of the sea is 255.5 kPa. It is important to note that the density of seawater and the acceleration due to gravity were given in the problem, and the atmospheric pressure was provided as a reference value to add to the gauge pressure. It is also important to remember to use consistent units in calculations, so the density of seawater should be converted to kg/m3 to match the units of g.

I hope this helps you understand how to approach and solve this problem. Remember to always carefully read and understand the given information and use the appropriate equations to solve the problem.
 

1. What is pressure?

Pressure is defined as the amount of force applied per unit area. In scientific terms, it is the force acting on a surface divided by the area of that surface. It is typically measured in units of Pascals (Pa) or Newtons per square meter (N/m²).

2. How is pressure related to density?

Pressure and density are indirectly related. As the density of a substance increases, the particles within it become more closely packed together, resulting in more collisions and an increase in pressure. Conversely, a decrease in density leads to a decrease in pressure.

3. What is atmospheric pressure?

Atmospheric pressure is the force per unit area exerted by the weight of the Earth's atmosphere on a surface. It is caused by the weight of air molecules in the atmosphere and is measured in units of Pascals (Pa) or millibars (mb).

4. How does atmospheric pressure change with altitude?

As altitude increases, the atmospheric pressure decreases. This is due to the fact that as you move higher in the atmosphere, there are fewer air molecules above you, resulting in a decrease in the force exerted by the weight of the atmosphere.

5. What is the relationship between atmospheric pressure and weather?

Atmospheric pressure plays a key role in determining weather patterns. High pressure systems typically bring clear, dry weather, while low pressure systems are associated with cloudy, wet conditions. Changes in atmospheric pressure can also indicate approaching storms or changes in weather patterns.

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