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Special Relativity and Blue Shift question |
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| Jan21-13, 07:30 PM | #1 |
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Special Relativity and Blue Shift question
Earlier today I was on youtube when I saw this comment
I know that no matter what you wouldn't be able to see Earth in that much detail but that's not the point. Would time dilation keep you inside the visible spectrum (but still slightly blue shifted)? Assuming you were able to see the full spectrum would things appear significantly sped up or would your time slowing down make them seem to move only slightly faster? Does time dilation even apply here? |
| Jan21-13, 07:40 PM | #2 |
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| Jan21-13, 07:56 PM | #3 |
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Austin0 is correct; relativistic Doppler shift would cause the incoming light signals from Earth to appear "speeded up" to you.
Think of it this way: suppose you start 100 light years away from Earth at this instant (in the Earth's rest frame) and travel to Earth at 0.5c (half the speed of light). That means you will arrive on Earth 200 years from this instant, Earth time. But when you started, you were seeing light from Earth 100 years before this instant; so in the 200 years (Earth time) that you travel, 300 years' worth of light signals from Earth will reach you (because when you reach Earth, of course you are seeing light signals from Earth instantly, with no time delay). Plus, since you are traveling at 0.5c, less than 200 years pass by your clock during the journey. It turns out that only a little over 173 years will pass for you during the journey. So in 173 years of elapsed time by your clock, you will receive 300 years' worth of light signals from Earth. So you will be seeing events on Earth "speeded up" by a factor of 300/173 during your trip. |
| Jan21-13, 08:40 PM | #4 |
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Special Relativity and Blue Shift question
Thank you both that was incredibly easy to understand and incredibly interesting to think about.
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| Jan21-13, 09:45 PM | #5 |
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Just one additional comment: 300/173 is the relativistic Doppler shift factor at a relative velocity of 0.5c--actually if you do the precise math the Doppler shift factor is sqrt(3), and the elapsed time by the traveler's clock is 100 * sqrt(3) years, so we have the "speed-up" ratio 300 / (100 * sqrt(3)) = 3 / sqrt(3) = sqrt(3), exactly equal to the Doppler shift factor. It's easy to show that this holds generally, so as Austin0 said, the "speed-up" applies to any signals received, and it applies at any relative velocity.
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| Jan21-13, 11:35 PM | #6 |
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| Jan22-13, 07:12 PM | #7 |
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