Kinetic and static frictional forces

[Leestyn]

static and frictional forces applied to a block. what is the horizontal force required to start the box from moving. known is kinetic friction - .600 and static friction .800 the block has a mass of 755N

 

[LowlyPion]

static and frictional forces applied to a block. what is the horizontal force required to start the box from moving. known is kinetic friction - .600 and static friction .800 the block has a mass of 755N

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How is the coefficient of friction related to the weight?

 

[baba89]

I can provide a response to the content regarding kinetic and static frictional forces and the horizontal force required to start a block from moving.

Firstly, let's define kinetic and static frictional forces. Kinetic friction is the force that opposes the motion of an object when it is already in motion. On the other hand, static friction is the force that opposes the motion of an object when it is at rest. Both of these forces are a result of the interaction between two surfaces in contact with each other.

In the given scenario, we are dealing with a block with a mass of 755N. This means that the weight of the block is 755N, which is equal to its mass (in kg) multiplied by the acceleration due to gravity (9.8 m/s^2).

Now, let's look at the known values of kinetic friction and static friction, which are 0.600 and 0.800 respectively. These values represent the coefficient of friction, which is a measure of the roughness or smoothness of the surfaces in contact. A higher coefficient of friction means that the surfaces are rougher and will result in a greater force of friction.

To calculate the horizontal force required to start the block from moving, we need to understand the relationship between the force of friction and the applied force. According to Newton's first law, an object at rest will remain at rest unless acted upon by an external force. In this case, the external force is the force applied to the block.

The minimum force required to overcome the static friction and start the block moving is equal to the product of the coefficient of static friction and the normal force (which is equal to the weight of the block). Therefore, the horizontal force required to start the block from moving is 0.800 x 755N = 604N.

Once the block is in motion, the force of kinetic friction will come into play and will oppose the motion. The force of kinetic friction is equal to the coefficient of kinetic friction multiplied by the normal force. Therefore, the force of kinetic friction in this scenario would be 0.600 x 755N = 453N.

In conclusion, the horizontal force required to start the block from moving is 604N, which is equal to the product of the coefficient of static friction and the weight of the block. Once the block is in motion, the force of kinetic friction will be