Energy Conserved in momentum problem

In summary, a 4.0kg bowling ball with an initial velocity of 8.0 m/s collides elastically with another 4.0kg ball at rest, causing the first ball to stop after the collision. The resulting velocity of the second ball can be calculated using the equation m1v1+m2v2 = m1v1' + m2v2'. This collision is perfectly elastic as there is no loss of energy, and PE is not a factor in this problem.
  • #1
Woopy
149
0

Homework Statement


A 4.0kg bowling ball rolling to the right at 8.0 m/s has an elastic head-on collision with another 4.0kg ball initially at rest. The first ball stops after the collision.
a) Find the velocity of the canoe after the collision?
b) Is the collision perfectly elastic? (show work)
c) Is energy conserved? (show work)

Homework Equations


m1v1+m2v2 = m1v1' + m2v2'
PE=KE
mgh=1/2mv2

The Attempt at a Solution


a) (4.0kg)(8.0m/s) + (4.0kg)(0 m/s) = (4.0kg)(0 m/s) + (4.0kg)(v2')
32 kgm/s + 0 kgm/s = 0 kgm/s + 4.0kg(v2')
8 m/s = v2'

b) Don't know how to tell if it is perfectly elastic, no equation that I can think of

c) Don't know how to tell if energy is conserved, no equation that I can think of
 
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  • #2
What equations do you know of that deals with energy?
 
  • #3
I know KE = PE, and that is 1/2 mv2 = mgh
 
  • #4
So we know that in an elastic collision, energy is conserved, right? So is there a way to compare the before and after collision energy?
 
  • #5
I do know that no energy is lost, so that means energy is conserved. As to a way to compare the before and after collision energy..I'm sifting through my notes and not seeing anything glaring out.
 
  • #6
Well, you could calculate the energy of the system before and after, right?

Hint: Kinetic energy.
 
  • #7
.5(4.0kg)(8.0m/s)2 = 128 J = .5(4.0kg)(8.0 m/s)2

oh...so the KE is the same on both sides, so no energy is lost.

and if no energy is lost, then it has to be perfectly elastic?
 
  • #8
Yup, simple as that!
 
  • #9
Woopy said:

Homework Statement


A 4.0kg bowling ball rolling to the right at 8.0 m/s has an elastic head-on collision with another 4.0kg ball initially at rest. The first ball stops after the collision.

Homework Equations


m1v1+m2v2 = m1v1' + m2v2'
PE=KE
mgh=1/2mv2
You should also be aware that PE has nothing to do with this problem. Typically, you don't consider PE in collision problems between hard particles (eg. bowling balls), gravitational or otherwise. An exception would be if the balls were rolling on a slanted surface, or if a ball collides with a spring, but usually you just ignore PE in a collision problem.
 

1. What is the law of conservation of momentum?

The law of conservation of momentum states that in a closed system, the total momentum before and after a collision will remain constant. This means that the total momentum of all objects involved in the collision will not change, regardless of any internal forces acting between the objects.

2. How is momentum conserved in collisions?

In collisions, momentum is conserved through the exchange of forces between objects involved. When two objects collide, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

3. What is the difference between elastic and inelastic collisions in terms of momentum conservation?

In elastic collisions, both kinetic energy and momentum are conserved. This means that the total momentum of the objects before and after the collision remains the same, as well as the total kinetic energy. In inelastic collisions, only momentum is conserved, while some kinetic energy is lost due to deformation or heat.

4. How does the mass and velocity of objects affect the conservation of momentum?

The mass and velocity of objects play a crucial role in the conservation of momentum. Objects with larger masses have a greater momentum, while objects with higher velocities have a greater kinetic energy. In a collision, the total momentum of the system will remain constant, but the distribution of momentum between the objects may change depending on their respective masses and velocities.

5. What are some real-life examples of momentum conservation?

In everyday life, momentum conservation can be observed in various scenarios such as car crashes, billiard ball collisions, or even a person jumping off a diving board. In all of these cases, the total momentum of the system before and after the event remains the same, demonstrating the law of conservation of momentum.

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