Is this problem done properly?

  • Thread starter Ion1776
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In summary, the magnitude of the momentum of the monkey and scooter is 224 and the magnitude of the momentum of the chimpanzee and roller skates is 66. The ratio between the two is 3.40.
  • #1
Ion1776
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At a circus animal training facility, a monkey rides a miniature motorscooter at a speed of 7.0 m/s. The monkey and scooter together have a mass of 32 kg. Meanwhile, a chimpanzee on roller skates with a total mass of 44 kg moves at a speed of 1.5 meters per second. The magnitude of the momentum of the monkey plus scooter is how many times the magnitude of the momentum of the chimpanzee plus skates?

Monkey/scooter=P=(32 kg)(7.0 m/s)=224

Chimp/rollers= (44kg)(1.5 m/s)= 66

=224/66=3.40
 
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  • #2
Still need some input on this please?
 
  • #3
Ion1776 said:
Monkey/scooter=P=(32 kg)(7.0 m/s)=224

Chimp/rollers= (44kg)(1.5 m/s)= 66

=224/66=3.40
Looks good to me.
 

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