Beat FrequencyWhat is the new tension in the string that slipped?

In summary, two identical strings with a fundamental frequency of 156 Hz and under 228 N of tension each, create a beat frequency of three beats per second when one string's tension is reduced slightly due to a slipping peg. To find the new tension in the slipped string, we can use the formula f1/f2 = (T1/T2)^1/2, where f1 and f2 are the frequencies of the two strings and T1 is the original tension. Solving for T2, we get a tension of approximately 223.6 N for the slipped string. However, without more information such as linear density or wave speed, this calculation may not be entirely accurate.
  • #1
r_swayze
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Two identical strings are sounding the same fundamental tone of frequency 156 Hz. Each string is under 228 N of tension. The peg holding one string suddenly slips, reducing its tension slightly, and the two tones now create a beat frequency of three beats per second. What is the new tension in the string that slipped?

My attempt so far:

fbeat = f1 - f2 = 3Hz

f1 = 156Hz

3Hz - 156Hz = -f2

f2 = 153Hz

So how do I find the tension for this frequency? Usually there is more information given such as the linear density or speed of the wave. I don't see how I can find the tension without those variables. Any help?
 
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  • #2
For identical strings frequency f = k*(T)^1.2, where k is constant and T is the tension in the string. So
f1/f2 = (T1/T2)^1/2.
You have already found f1 and f2. T1 is given. Find T2.
 
  • #3


As a scientist, it is important to have all the necessary information to accurately solve a problem. In this case, the frequency and tension of the strings are given, but the linear density or speed of the wave is missing. Without this information, it is not possible to calculate the new tension in the string that slipped.

The linear density of a string refers to its mass per unit length, while the speed of a wave on a string depends on the tension and linear density of the string. Therefore, without knowing the linear density, we cannot accurately determine the new tension in the string.

It is also worth noting that the beat frequency is not directly related to the tension of the string but rather to the difference in frequency between the two strings. In this case, the beat frequency is 3Hz, but we cannot use this information to determine the new tension in the string that slipped.

In conclusion, without additional information, it is not possible to accurately determine the new tension in the string that slipped. As a scientist, it is important to have all the necessary data to accurately solve a problem and draw conclusions.
 

1. What is beat frequency?

Beat frequency is the difference between two frequencies that are being played or produced at the same time. It is a measure of the oscillation rate of a sound wave.

2. How is beat frequency calculated?

Beat frequency is calculated by subtracting the lower frequency from the higher frequency. For example, if one frequency is 200 Hz and the other is 205 Hz, the beat frequency would be 5 Hz.

3. How does beat frequency affect the sound we hear?

Beat frequency can create a pulsing or throbbing sound, as the two frequencies combine and interfere with each other. This can result in a perceived increase or decrease in volume, depending on how the waves are aligned.

4. What causes beat frequency?

Beat frequency is caused by the overlapping of two sound waves with slightly different frequencies. This can occur when two instruments are playing slightly out of tune with each other, or when a single instrument produces two notes simultaneously.

5. How can beat frequency be used in music or acoustics?

Beat frequency can be used to tune instruments, as it can help identify when two notes are not perfectly in tune with each other. It can also be used in audio engineering to create special effects or enhance the quality of music recordings.

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