To find the flux through that surface you need to "integrate" E*dA over the surface. But where is surface a*b? It's location is important, since the field varies with x coordinate.kdp58 said:ok... the problem says that there is an enclosed surface with a=b=.436 m and c=.582 m. (forming a rectangular prism)
the electric field is passing perpendicularly through the surface a*b which is .190 m^2
An electric field is a force field that surrounds an electrically charged particle or object. It exerts a force on other charged particles or objects within its field.
The strength of an electric field is measured in units of volts per meter (V/m). This represents the amount of force that would be exerted on a charged particle placed in the electric field.
An electric field is a force field, while an electric potential is the amount of work required to move a unit of charge from one point to another in an electric field. In other words, an electric field is a measure of the force acting on a charge, while electric potential is a measure of the energy associated with that force.
The strength of an electric field is inversely proportional to the square of the distance from the source of the field. This means that as the distance increases, the strength of the electric field decreases.
Electric fields are used in a variety of everyday devices such as televisions, computers, and cell phones. They are also used in medical devices such as MRI machines and defibrillators. Additionally, electric fields are used in power generation and transmission, as well as in various types of motors and generators.