- #1
MercuryRising
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find the inverse of y= x + sinx
i got as far as x=y+siny..but how do i get to y= ____?
thanks
i got as far as x=y+siny..but how do i get to y= ____?
thanks
I think they mean to write an expression that has "g(x)" in it. In other words just substitute g(x) for x in f(x)=x+sin(x).MercuryRising said:since it seems like that finding the inverse is beyond high school calculus..maybe my approach to the probelm was incorrect
the probelms states f(x) = x + sin(x), g(x) is the inverse of f(x) so f(g(x)) = x
a) write an expression for f(g(x)) in terms of g(x) and
b) use f(g(x))= x to find g'(x) in terms of g(x)
i do not understand what it means by writing an expression interms of g(x) when i have no idea how to find the inverse..
I think that's what they wanted. Now just solve for g'(x).MercuryRising said:ok.. so f(g(x)) = g(x) + sin(g(x)) = x
to find g'(x) in terms of g(x) i did
g'(x) + (g'(x))cos(g(x)) = 1..wait that doesn't seem right
Remember that if f(x) and g(x) are inverse functions thenMercuryRising said:ok... so g'(x) = 1/ 1 + cos(g(x))
now they want g'(pi)...and I am stuck again, i can't find any trig identities that can help me in g'(x)
The inverse function of y = x + sinx is y = x - sinx.
To find the inverse of a function, switch the x and y variables and solve for y.
The domain of the inverse function y = x - sinx is all real numbers. The range is also all real numbers.
No, the inverse function of y = x + sinx is y = x - sinx, which is not the same as the original function.
Yes, you can graph the inverse function y = x - sinx on the same graph as the original function by reflecting the graph of y = x + sinx across the line y = x.