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bigdaddydark7
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what is the initial velocity when:
Horizontal displacement= 1.51
Vertical displacement= -.273
angle launched= 36
Horizontal displacement= 1.51
Vertical displacement= -.273
angle launched= 36
Is there any units for the displacements.bigdaddydark7 said:could someone at least tell me the equations i need to use, because i am totally lost
The equation for finding initial velocity given vertical and horizontal displacement is v0 = √(g*dy / sin(2θ)), where v0 is the initial velocity, g is the acceleration due to gravity (9.8 m/s2), dy is the vertical displacement, and θ is the angle of launch.
The angle of launch can be calculated using the equation θ = 1/2 * tan-1((g*dx) / (v02)), where θ is the angle of launch, g is the acceleration due to gravity, dx is the horizontal displacement, and v0 is the initial velocity.
The units for initial velocity when using this equation are meters per second (m/s).
Yes, this equation can be used for any projectile motion scenario as long as the initial vertical and horizontal displacements are known.
Yes, air resistance can affect the accuracy of this equation as it does not take into account the external forces acting on the projectile. This equation is most accurate when air resistance is negligible.