Calculating Solar Panel Power Output: Chain Rule & Arcsin Function

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This represents the change in power output with respect to time. In summary, the power output of a solar panel varies with the angle of the sun and can be calculated using the chain rule. The function θ(t) can be used to calculate θ'(t) and find the change in power output between 4:30PM and 5:30PM. The change in power output is represented by dP/dt.
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IntegrateMe
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The power output of a particular type of solar panel varies with the angle of the sun shining on the panel. The panel outputs P (θ) watts when the angle between the sun and the panel is θ for 0 ≤ θ ≤ π. On a typical summer day in Ann Arbor, the angle between a properly mounted panel and the sun t hours after 6 a.m. is θ(t) for 0 ≤ t ≤ 14. Assume that sunrise is at 6 a.m. and sunset is 8 p.m.

(A) Calculate dP/dt using the chain rule, and give interpretations for each part of your calculation.

P(θ(t)). So, dP/dt = P(θ(t))' = P'(θ(t)) * θ'(t)
P'(θ(t)) is the average rate of change of power with respect to θ.
θ'(t) is the average rate of change of θ with respect to t.

(B) Suppose θ(t) = arcsin(t/7 -1) + π/2. Calculate θ'(t) using the equivalent expression: sin(θ(t) - π/2) = t/7 - 1

I just differentiated the equivalent function:

cos(θ(t) - π/2)*θ'(t) = 1/7
θ'(t) = 1/(7*cos(θ(t) - π/2))

(C) Suppose dP/dθ (2π/3) = 12 and θ(t) is the function in part (B). Find the change in power output between 4:30PM and 5:30PM.

This is where I'm having trouble. I would think the "change in power output" would simply be dP/dθ, since this represents the change in power with respect to θ, but I feel as though I'm incorrect here. Any help would be awesome. Thanks!
 
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Change in power output is dP/dt here.
 

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