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jazzyfizzle
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Since you don't have numbers, you'll express your answer in terms of the given data--F0, t0, and m.jazzyfizzle said:But that's the thing.. I don't know the force. How are you supposed to even do this when there's no numbers involved ?
You're on the right track. Hint: Treat each segment of the motion separately. In the first segment (from t = 0 to t0), the initial speed is zero--but that's not the case for the second half of the motion.I just tried it and got :
x=2[(1/2)(F0/m)t^2]
There's a much easier way to find the final velocity of the first segment. What's the definition of acceleration?jazzyfizzle said:Should I maybe use vf^2=vi^2+2ax to find the final velocity of the first segment?
then go from there ?
No, it's not.jazzyfizzle said:For a final answer I got
x=((2F0*t0^2)/m)) + (4F0t0)/m
But... I don't think that's right at all...
Good! You have the first segment done.jazzyfizzle said:Ok what I did was :
First I used x=v0t+1/2at^2 to find the distance traveled for the first segment before the force doubled
I plugged in a=(F/m) for the acceleration and v0=0 for the initial velocity
Then i got
x=1/2(F0/m)t^2
for the first segment
Good. An easier way would be to use vf = vi + at, but your way is perfectly fine.Then,
i used vf^2=vi^2+2ax to find the final velocity of the first segment
(plugging in the x i found from above and a=F/m and v0=0)
which i got to be
vf= (F0t)/m
That will give you the distance for the second segment. (Then you'll add that to what you already found for the first segment.)then I used that final velocity as the initial velocity for the 2nd segment
and plugged in a=2F0/m
into x=v0t+1/2at^2
I don't see how you got this. Show me what you plugged in where.and somehow came out with the answer
x=((2F0*t0^2)/m)) + (4F0t0)/m
That's not dimensionally correct. Show me what you plugged in for each term in the following:jazzyfizzle said:For the second segment I'm getting the distance as
[F0(3t0 + t0^2)]/m
v0 and a are correct, but the time for the second segment is the same as the first: t0. (From t0 to 2t0.)jazzyfizzle said:v0 ---> (F0t0)/m
t ----> 2
a -----> (2F0)/m
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