Differential equations proof

LCKurtz

You have A and B in terms of r and theta. You want r and theta in terms of A and B.

LCKurtz

You can get either a sine or cosine form. That shouldn't surprise you because anything that can be expressed as one can be expressed in terms of the other since ##\sin\theta = \cos(\frac \pi 2 -\theta)## and similarly for the cosine.

th3chemist

woud ε = be pi/2 - wt - theta?