- #1
Nick89
- 555
- 0
Hi,
I was recently wondering this, might be a stupid question but hey, here to learn :)...
Since the sound pressure level is defined as:
[tex]L_p = 20 log_{10} \left( \frac{p}{p_{ref}} \right)[/tex]
What would happen if you put a microphone in a perfect vaccuum? Obviously there can be no sound pressure [itex]p[/itex], so would the microphone measure a value of [itex]-\infty[/itex] dB? ([itex]lim_{x \rightarrow 0} log(x) = -\infty[/itex], right?)
Intuitively I would say no since with most microphones if you are in a completely silent room (except for thermal noise), they would measure 0 dB, right? And this would probably be the lowest spl the microphone can measure, any lower pressure will not move the vibrating coil?
Meh, just thought I'd ask.
I was recently wondering this, might be a stupid question but hey, here to learn :)...
Since the sound pressure level is defined as:
[tex]L_p = 20 log_{10} \left( \frac{p}{p_{ref}} \right)[/tex]
What would happen if you put a microphone in a perfect vaccuum? Obviously there can be no sound pressure [itex]p[/itex], so would the microphone measure a value of [itex]-\infty[/itex] dB? ([itex]lim_{x \rightarrow 0} log(x) = -\infty[/itex], right?)
Intuitively I would say no since with most microphones if you are in a completely silent room (except for thermal noise), they would measure 0 dB, right? And this would probably be the lowest spl the microphone can measure, any lower pressure will not move the vibrating coil?
Meh, just thought I'd ask.