I think you have to apply Gauss' law to the smaller plate on the theory that the field above the smaller plate and the charge distribution on it will be uniform. The charge distribution will not be uniform on the larger plate so the field will not be uniform. (Let's say the smaller plate is on the bottom). Applying Gauss' law to the smaller plate: [itex]EA = Q/\epsilon[/itex] or [itex]E = \sigma/\epsilon[/itex]OPIH said:I need to know how the capacitance of a capacitor built from a
square plate and a large rectangular plate compares to that of a
capacitor built from a circle and a large rectangular plate, if the
diameter of the circle equals the length of the side of the square.
A Square and Circle Capacitor is a type of capacitor that has either a square or circular shape. It is used to store electrical energy by creating an electric field between two conductive plates separated by a dielectric material.
The main difference between a square and circle capacitor is their shape. A square capacitor has a larger surface area and smaller distance between plates, resulting in higher capacitance compared to a circular capacitor. However, a circular capacitor has a more uniform distribution of electric field and can withstand higher voltages.
Square and circle capacitors have various applications in electronics, including power supply filtering, motor starting and running, and signal coupling. They are also used in high-frequency circuits, such as radio frequency filters and oscillators.
The capacitance of a square and circle capacitor can be calculated using the formula C = εA/d, where C is the capacitance in Farads, ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between the plates.
The capacitance of a square and circle capacitor is affected by the surface area of the plates, the distance between the plates, and the type of dielectric material used. Additionally, the shape and arrangement of the plates can also impact the capacitance.