Well, yes, that's just a restatement of the problem! You know that the slope of y= -3x+ b is -3. What connection is there between the slope of a tangent line and the function itself?I believe i would need to find the equation of the tangent to y=ax^3 when x=5 then that should be equal to -3x+b=y if I am not mistaken
A tangent line is a straight line that touches a curve at only one point and has the same slope as the curve at that point.
A secant line is a straight line that intersects a curve at two points, while a tangent line only touches the curve at one point.
The equation for a tangent line is y = mx + b, where m is the slope of the tangent line and b is the y-intercept.
The slope of a tangent line can be found using the derivative of the curve at the point where the tangent line touches the curve.
Tangent lines are used in engineering, physics, and other sciences to approximate the behavior of a curve at a specific point. They are also used in calculus to find the maximum and minimum values of a function.