- #1
Dulcis21
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Hi, the question, I'm having problems with is this:
A 1.0 mol sample of hydrogen gas has a temperature of 30 C. What is the total kinetic energy of all the gas molecules in the sample? How fast would a 75 kg person have to run to have the same kinetic energy?
Relevant equations:
K = (3/2)kT
or K = (3/2)nRT
Ok, so I tried using both formulas:
(3/2)(1.38*10^-23)(30+273) = 6.2721 * 10^-21
Then, since its one mole and the question asks for the total KE, I multiplied this answer by Avogadro's number (6.02*10^23) and got
= 3775.8042 Joules.
For the second part, I would just set this number equal to 0.5mv^2 and solve for v but since I got the first one wrong, it doesn't quite work :(
I really need help; I thought I had the right idea but it's not working out. Thanks
A 1.0 mol sample of hydrogen gas has a temperature of 30 C. What is the total kinetic energy of all the gas molecules in the sample? How fast would a 75 kg person have to run to have the same kinetic energy?
Relevant equations:
K = (3/2)kT
or K = (3/2)nRT
Ok, so I tried using both formulas:
(3/2)(1.38*10^-23)(30+273) = 6.2721 * 10^-21
Then, since its one mole and the question asks for the total KE, I multiplied this answer by Avogadro's number (6.02*10^23) and got
= 3775.8042 Joules.
For the second part, I would just set this number equal to 0.5mv^2 and solve for v but since I got the first one wrong, it doesn't quite work :(
I really need help; I thought I had the right idea but it's not working out. Thanks
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