Finding the Kinetic Friction Coefficient

[Einstein X9]

Homework Statement

A 22kg box is being pulled across a flat surface by a rope at a 25 degree angle with the floor. What is the kinetic friction coefficient?

Homework Equations

(Fnet)y= -mg + Tsin() + n(normal force)
(Fnet)x= Tcos() + kf

The Attempt at a Solution

I cannot figure out what Tension would be...Our professor gave us the FnetY equation and i feel like we need more information to figure this out. Its on my quiz tomorrow it would really help if someone could explain a little bit of what's going on. Thanks a bunch!

 

[anathema]

Thank you for your question. It seems like you are on the right track with using the equations for net force in the y and x directions. The tension in the rope, T, is the force that is pulling the box in the x direction. In order to find the kinetic friction coefficient, you will need to use the equation Fnetx = Tcos(theta) + kf, where theta is the angle of the rope with the floor.

To find the tension, you can use the equation Fnety = -mg + Tsin(theta) + n, where n is the normal force. Since the box is being pulled at an angle, the normal force will not be equal to the weight of the box, but it can be calculated using the angle and the weight of the box. Once you have the tension, you can plug it into the equation for Fnetx to find the kinetic friction coefficient.

I hope this helps and good luck on your quiz tomorrow! Remember to always make sure your units are consistent and to double check your calculations. If you have any further questions, please don't hesitate to ask. Keep up the good work!