- #1
Jones1987
- 77
- 0
Hi, I'm researching into what will be the best size wheels to put onto a motor to allow my robot to climb an incline, and then possibly find out what is the maximum incline it can reach.
I'm using this thread as a source for the math:
http://forums.trossenrobotics.com/archive/index.php/t-2900.html
But where he states this
"So, given 47 oz-in of torque with four motors (1.3 Newton-meters), mass of 2 Kg and an angle of 15 degrees, the answer is:
r = 1.3 / (9.8 * 2 * 0.26) = 0.26 m"
Would you not use the torque of a single motor to find out its max wheel size? Rather than combine the total torque and use that?
Also, once I've found my ideal size of wheel to tackle a 15degree incline, I'm taking an educated guess that a wheel to combat a 20degree incline be a smaller?
I'm using this thread as a source for the math:
http://forums.trossenrobotics.com/archive/index.php/t-2900.html
But where he states this
"So, given 47 oz-in of torque with four motors (1.3 Newton-meters), mass of 2 Kg and an angle of 15 degrees, the answer is:
r = 1.3 / (9.8 * 2 * 0.26) = 0.26 m"
Would you not use the torque of a single motor to find out its max wheel size? Rather than combine the total torque and use that?
Also, once I've found my ideal size of wheel to tackle a 15degree incline, I'm taking an educated guess that a wheel to combat a 20degree incline be a smaller?