Questions about the Schwarzschild metric

In summary, the Komar approach is more in line with general relativity's predictions than the Schwarzschild approach.
  • #1
nick41
4
0
Hello everybody! I have some questions concerning the structure of the Schwarzschild metric, which is given by
$$ ds^2=-(1- \frac{2GM}{r})dt^2+(1-\frac{2GM}{r})^{-1}dr^2+ r^2(d\theta^2+ \sin^2(\theta) d\phi^2) $$
where we set $c=1$. I would like to know the following: \\
\\
1. Why is it reasonable to consider $M$ as the mass of the black hole? What is the motivation behind this? \\
\\
2. What are the geodesics in the Schwarzschild solution? Is there any good way to visualize them all at once?
\\
\\
Every answer would be appreciated
 
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  • #2
nick41 said:
1. Why is it reasonable to consider $M$ as the mass of the black hole? What is the motivation behind this?

Put simply, M is the mass you will obtain if you put a small test object in orbit about the hole, measure its orbital parameters, and apply Kepler's Third Law.

nick41 said:
2. What are the geodesics in the Schwarzschild solution? Is there any good way to visualize them all at once?

Probably not; there are too many different kinds. A couple of types that are commonly considered are:

(1) Purely radial timelike geodesics, particularly infalling ones; these represent the worldlines of objects that are free-falling into the hole.

(2) Tangential timelike geodesics, which represent the worldlines of objects that are orbiting the hole.
 
  • #3
nick41 said:
1. Why is it reasonable to consider $M$ as the mass of the black hole? What is the motivation behind this?

There doesn't have to be a black hole at all - the Schwarzschild solution works just fine in the empty space around any stationary spherically symmetric mass. You only get a black hole if the object is so dense that r=2M lies above its surface.
 
  • #4
nick41 said:
Hello everybody! I have some questions concerning the structure of the Schwarzschild metric, which is given by
$$ ds^2=-(1- \frac{2GM}{r})dt^2+(1-\frac{2GM}{r})^{-1}dr^2+ r^2(d\theta^2+ \sin^2(\theta) d\phi^2) $$
where we set $c=1$. I would like to know the following: \\
\\
1. Why is it reasonable to consider $M$ as the mass of the black hole? What is the motivation behind this? \\
\\
2. What are the geodesics in the Schwarzschild solution? Is there any good way to visualize them all at once?
\\
\\
Every answer would be appreciated

As others have pointed out, if you look at the orbits of bodies far away from the black hole, where gravity is nearly Newtonian, you can find that the Newtonian limit gives M as the mass of the black hole.

The geodesics of the Schwarzschild solution are just the various orbits of unaccelerated test particles. These include orbits that go around the black hole, go into it, or fly by it, as long as the test particle in question a) isn't accelerating like a rocket and b) isn't so big that its own gravity perturbs the metric and c) you don't have significant emission of gravitational radiation, which would also cause the test particle to accelerate.
 
  • #6
haushofer said:
For a more formal treatment, see e.g. Townsend's notes on black holes,

http://arxiv.org/pdf/gr-qc/9707012v1.pdf

chapter 5 (Komar integrals).

Note though that while in the exterior region the Komar formula gives you the Schwarzschild mass parameter M, it doesn't give you the same distribution of mass in the interior region as the fairly well known integral, valid only in Schwarzschild coordinates

[itex] m(r) = \int \rho(r) 4 \pi r^2 dr [/itex]

does. The difference won't matter with a Schwarzschild black hole, but it will matter with a a Schwarzschild non-black hole solution in the interior region (not the exterior region though).

The easiest way of convincing oneself of this is direct calculation, the particular case that convinced me was the "box of light" case. I'm not sure I've seen much comment on this difference, though the fact that Townsend mentions specifically showing it's equal in the exterior region is suggestive of the issues that arise in the interior region.

In the box of light case, the Schwarzschild formula will suggest a mass that increases monotonically as r increases. In the idealized "box of light" case, where the box is a sphere of exotic matter with no mass but the tension required to hold the box together, you get a picture where the contribution of the exotic matter shell to the total mass is actually negative, obviously different from the monotonic increase in mass predicted by the Schwarzschild formula.

The total exterior mass remains the same in both cases, but the details of how it's distributed (and in particular, the contribution of the shell to the mass) varies with the two aproaches.This may sound funky, but the Komar approach correlates better to the gravitational fields one would measure by measuring the 4-acceleration of a static observer. This is because you can cast the Komar approach into a rather Gauss-law like integral (see Wald, for example, around pg 288).
 

1. What is the Schwarzschild metric?

The Schwarzschild metric is a mathematical equation that describes the geometry of spacetime around a non-rotating, spherically symmetric mass. It was developed by Karl Schwarzschild in 1916 as a solution to Einstein's field equations in general relativity.

2. What does the Schwarzschild metric tell us about black holes?

The Schwarzschild metric is used to describe the spacetime around a black hole, including its event horizon and singularity. It tells us about the curvature of spacetime caused by the immense gravitational pull of the black hole.

3. How is the Schwarzschild metric derived?

The Schwarzschild metric is derived from Einstein's field equations in general relativity, which relate the curvature of spacetime to the distribution of matter and energy. It involves solving a set of differential equations to find the mathematical description of spacetime around a non-rotating, spherically symmetric mass.

4. Can the Schwarzschild metric be used to describe other objects besides black holes?

Yes, the Schwarzschild metric can be used to describe the spacetime around any non-rotating, spherically symmetric mass, not just black holes. It has also been used to describe the orbits of planets and stars in our solar system.

5. What are some implications of the Schwarzschild metric?

The Schwarzschild metric has several important implications in astrophysics and cosmology. It provides a theoretical framework for understanding the behavior of black holes and has been used to make predictions about phenomena such as gravitational lensing and gravitational waves. It also serves as a foundation for more complex metrics that describe the spacetime around rotating objects.

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