- #1
UsualAnalyst
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Hello, i am new to the forums here so forgive me if I have mistakenly started a matching thread that already exists.
So i have a task for building a parallel plate capacitor for two aluminum plates connected to a battery on opposite terminals. The target capacitance is 2000 microfarads. with a distance of 0.062 inches between the plates. Oh yea, the units of length are inches.
Since the units for the general equations for capacitance are in either CGS or MKS units, this leaves me confused. So, i have a few questions before completing the experiment.
Questions:
1) Do the parallel plates have to be identical; meaning that they have to be of the same material?
2) For the dimensions of the plates, do they have to be absolutely the same? meaning that can one be smaller or larger than the other?
3) When finding the area of the plates, are the thicknesses of the plates taken into account. (I know Area is L * W, and adding the thickness would mean Volume; however, since voltage is flowing through the plates, i wonder about it.)
4) Since the units of length that i am obligated to use are in inches would that interfere with the equations that are given for Capacitance such as:
C = εrε0[itex]\frac{A}{d}[/itex]
C = εr[itex]\frac{A}{4*Pi*d}[/itex]
5) One final question, for the equation would be why is the 4*pi applied in the second equation or is it used to omit ε0 constant?
Please and thank you in advance for anyone's time.
So i have a task for building a parallel plate capacitor for two aluminum plates connected to a battery on opposite terminals. The target capacitance is 2000 microfarads. with a distance of 0.062 inches between the plates. Oh yea, the units of length are inches.
Since the units for the general equations for capacitance are in either CGS or MKS units, this leaves me confused. So, i have a few questions before completing the experiment.
Questions:
1) Do the parallel plates have to be identical; meaning that they have to be of the same material?
2) For the dimensions of the plates, do they have to be absolutely the same? meaning that can one be smaller or larger than the other?
3) When finding the area of the plates, are the thicknesses of the plates taken into account. (I know Area is L * W, and adding the thickness would mean Volume; however, since voltage is flowing through the plates, i wonder about it.)
4) Since the units of length that i am obligated to use are in inches would that interfere with the equations that are given for Capacitance such as:
C = εrε0[itex]\frac{A}{d}[/itex]
C = εr[itex]\frac{A}{4*Pi*d}[/itex]
5) One final question, for the equation would be why is the 4*pi applied in the second equation or is it used to omit ε0 constant?
Please and thank you in advance for anyone's time.