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Max bending in tapering rod |
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| Feb22-13, 05:49 AM | #18 |
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Max bending in tapering rod
Answer to post #16 is that you can test this proposal for yourself by letting x=0 and x=L to see if you get sensible answers (You don't). But it's nearly right.
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| Feb22-13, 05:57 AM | #19 |
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answer to post #17 is to use differential calculus. If you had numbers instead of symbols, you could plot the graph. The question doesn't ask for the maximum stress- just its location, which would be independent of W and pi.
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| Feb22-13, 06:04 AM | #20 |
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Thanks for your help |
| Feb22-13, 07:26 AM | #21 |
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Can you interpret stress=My/I where M, y and I are all functions of x? Then d(stress)/dx=0 will give you an equation in x, at least one of whose solutions will be what you are looking for.
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| Feb22-13, 08:27 AM | #22 |
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no i cant interperet it. thats what iv been sayin. i cant write what i know as an equation of x without having other terms which arnt included in the equation i need to prove. i dont understand how to do it. id appreciate it if you could just show me.
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| Feb22-13, 10:17 AM | #23 |
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Let f be the stress at section X
Let e be the diameter at section X Can you confirm that you agree with M=Wx, and e=d+x*(D-d)/L Also confirm that you have I=pi*e^4/64 where e is the function of x above. Putting all that together: f=My/I = (a function of x that you can put together) Put df/dx=0 and solve for x= |
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