Proof of Limit: $\varepsilon$-$\delta$ Definition

In summary, the $\varepsilon$-$\delta$ definition of a limit is a mathematical definition that precisely defines the concept of a limit in calculus. It is important because it allows for rigorous proofs of limit existence and value, and it is used in many important theorems and techniques in calculus. To use it to prove a limit, one must determine the limit, choose a value for $\varepsilon$, and find a corresponding value for $\delta$ that satisfies the definition. It can also be used to prove the continuity of a function. However, it has limitations, such as only being applicable to defined points and being difficult to use in more complex situations.
  • #1
kidia
66
0
Please I need help on this one.

Use the [tex]([/tex] [tex]\varepsilon[/tex] ,[tex]\delta[/tex] [tex])[/tex] definition of limit to prove that

lim [tex]([/tex]x+y/[tex]x^2[/tex]+[tex]y^2[/tex]+1[tex])[/tex]=0
(x,y)[tex]\rightarrow[/tex](0,0)
 
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  • #2
Well, what have you done on this so far? Do you know of any similar problems that you do know how to do?

By the way, I'm pretty sure you meant (x+y)/(x²+y²+1), not x+y/x²+y²+1.
 
  • #3
No Hurkyl,I haven't done this kind of limit help me.And it is

lim [tex]([/tex]x+y/[tex]x^2[/tex]+[tex]y^2[/tex]+1[tex])[/tex]=0
(x,y)[tex]\rightarrow[/tex](0,0)
 

1. What is the $\varepsilon$-$\delta$ definition of a limit?

The $\varepsilon$-$\delta$ definition of a limit is a mathematical definition that is used to precisely define the concept of a limit in calculus. It states that for a function $f(x)$, the limit of $f(x)$ as $x$ approaches a specific value $c$ is equal to $L$ if for any positive value of $\varepsilon$, there exists a positive value of $\delta$ such that when the distance between $x$ and $c$ is less than $\delta$, the distance between $f(x)$ and $L$ is less than $\varepsilon$.

2. Why is the $\varepsilon$-$\delta$ definition important?

The $\varepsilon$-$\delta$ definition is important because it provides a rigorous and precise definition of the concept of a limit in calculus. It allows us to prove the existence of limits and their values, and it is the foundation for many important theorems and techniques in calculus.

3. How do you use the $\varepsilon$-$\delta$ definition to prove a limit?

To use the $\varepsilon$-$\delta$ definition to prove a limit, you must first determine the limit you are trying to prove. Then, you must choose a value for $\varepsilon$ and use algebraic manipulations to find a corresponding value for $\delta$ that satisfies the definition. Finally, you must show that for any value of $\varepsilon$, there exists a value of $\delta$ that satisfies the definition.

4. Can the $\varepsilon$-$\delta$ definition be used to prove the continuity of a function?

Yes, the $\varepsilon$-$\delta$ definition can be used to prove the continuity of a function. If a limit exists for a function $f(x)$ at a specific point $c$, and the value of the limit is equal to $f(c)$, then $f(x)$ is continuous at $c$ according to the $\varepsilon$-$\delta$ definition.

5. Are there any limitations to the $\varepsilon$-$\delta$ definition of a limit?

One limitation of the $\varepsilon$-$\delta$ definition is that it only applies to functions that are defined at a specific point $c$. It cannot be used to prove the existence or non-existence of limits at points where a function is not defined. Additionally, it can be difficult to use the definition in more complex situations, such as when dealing with multi-variable functions or sequences.

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