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phyzmatix
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Homework Statement
A heavily damped simple harmonic system is displaced a distance F from its equilibrium positio and released from rest. Show that in the expression for the displacement
[tex]x=e^{-pt}(F\cosh qt + G\sinh qt)[/tex]
where
[tex]p=\frac{r}{2m}[/tex]
and
[tex]q=(\frac{r^2}{4m^2}-\frac{s}{m})^{\frac{1}{2}}[/tex]
that the ratio
[tex]\frac{G}{F}=\frac{r}{(r^2-4ms)^{\frac{1}{2}}}[/tex]
2. The attempt at a solution
I've been thinking and thinking and thinking, but no luck. I'd really appreciate it if someone could just tell me where to start.
Thanks!
phyz