- #1
phyyy
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Homework Statement
The following describes the position of a body as a function of time: [itex]X(t)=9\cdot cos(1.2t)\cdot e^{-t/10}[/itex].
What is the velocity of the body at t=17sec ?
2. The attempt at a solution
I'm trying to use the formula [itex]v(t)=\frac{dr}{dt}[/itex] in order to get the velocity and I get: [itex]-9\cdot e^{\frac{-17}{10}}\cdot [sin(1.2\cdot 17)\cdot 1.2+\frac{1}{10}\cdot cos(1.2\cdot 17)]=-1.975[/itex]
I guess negative velocity means the body is traveling in the oposite direction but is seems a little odd. Could this be the right answer?