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Differentiating |
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| Dec1-05, 12:07 AM | #1 |
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Differentiating
ok, so my problem goes like this:
I have that the integral of dx/((cx+a)(dx+b))=1/(ad-bc)lnabs((dx+b)/cx+a)) + C I have to use differentiation to verify the integration formulas. So far I've gotten to: D(1/(ad-bc)lnabs((dx+b)/cx+a)))=(1/ad-bc)((cx=a)/(dx+b)) => (cx+a)/((ad-bc)(dx+b)) where do I go from here to get back to the original integration formula?
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| Dec1-05, 12:30 AM | #2 |
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Recognitions:
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You differentiation is at fault.
if you have F = ln{f(x)/g(x)}, then F = lnf(x) - lng(x) dF/dx = f'/f - g'/g where f' = df/dx, g' = dg/dx |
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