Uncertainty question

by Pepsi24chevy
Tags: uncertainty
 Sci Advisor HW Helper P: 2,002 You are not asked about the velocity. You are asked about the uncertainty in momentum. So you got $\Delta x \Delta p \geq \hbar$ (or without the bar, depening on what version your book has). So you know $\Delta x$, that was given and you are asked the minimum value $\Delta p$ can take without violating the inequality. You should be able to tell that immediately from the equation. Or least least without reference to other relations.
 Quote by Galileo You are not asked about the velocity. You are asked about the uncertainty in momentum. So you got $\Delta x \Delta p \geq \hbar$ (or without the bar, depening on what version your book has). So you know $\Delta x$, that was given and you are asked the minimum value $\Delta p$ can take without violating the inequality. You should be able to tell that immediately from the equation. Or least least without reference to other relations.
 Sci Advisor HW Helper P: 2,002 Uncertainty question That's right. Simply $\Delta p_{min}=\hbar/\Delta x$. What would you be missing?