|Dec7-05, 11:52 PM||#1|
You have twelve coins, eleven identical and one different. You do not know whether the "odd" coin is lighter or heavier than the others. Someone gives you a balance and three chances to use it. The question is: How can you make just three weighings on the balance and find out not only which coin is the "odd" coin, but also whether it's heavier or lighter?
|Dec10-05, 07:18 PM||#2|
this has been posted here repeatedly. There's a variation to this coin problem that is much more complex, I saw it at "ibm ponder this" a couple of years ago....it makes this problem seem too easy. You can search there "ponder this" database if you want a real challenge.
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