What is the Coefficient of Restitution in a Block Collision with a Wall?

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SUMMARY

The coefficient of restitution (e) in a block collision with a wall can be calculated using the formula e = (relative velocity of separation) / (relative velocity of approach). In the discussed scenario, a block with mass m1 = 2 kg is pushed towards a wall with an initial velocity of v = 7 m/s and experiences kinetic friction with a coefficient of mK = 0.4. After rebounding off the wall, the block travels a distance of d2 = 1 m before stopping, which is essential for determining the velocities involved in the calculation of e.

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  • Understanding of classical mechanics principles
  • Knowledge of kinetic friction and its effects
  • Familiarity with the concept of relative velocity
  • Basic mathematical skills for applying formulas
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SuperGeek
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Hi all,
I am trying to find the coefficient of restitution in this example:
Block m1=2 kg is pushed with initial velocity v=7 m/s for distance
d = 4 meters towards a wall. Kinetic friction b/w floor and block is mK = 0.4. The block rebounds off the wall and travels distance
d2 = 1 m before stopping.

I think I should get the speeds of the block right before and after hitting the wall first but I am really lost on this one. Any help or teaching would be appreciated.
 
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First of calculate the relative velocity of approach and separation

e= coefficient of restitutio is given by relative velocity of separation along the normal divided by relative velocity of approach
 
Note to SuperGeek: You posted this in the Classical Physics section, check there for my response.

PS: Bad Dog for posting twice!
 

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