Calculating Mass of Acid in Vinegar

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Discussion Overview

The discussion revolves around calculating the mass of acetic acid in vinegar based on a neutralization reaction with sodium hydroxide. Participants explore the molar mass of acetic acid and the steps to determine the mass of acid present in a given volume of vinegar, involving stoichiometry and molarity calculations.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant outlines the neutralization reaction between acetic acid and sodium hydroxide, providing specific volumes and concentrations used in the experiment.
  • Another participant confirms the calculation of moles of sodium hydroxide and states that the moles of acetic acid are equal due to the 1:1 stoichiometry of the reaction.
  • There is a clarification regarding the molar mass of acetic acid, with one participant stating it is 60 grams per mole, while another initially misinterprets the calculated mass of acetic acid as its molar mass.
  • Participants discuss the method of calculating the mass of acetic acid by multiplying the number of moles by the molar mass, leading to a mass of 0.948 grams.

Areas of Agreement / Disagreement

Participants generally agree on the molar mass of acetic acid being 60 grams per mole and the method for calculating the mass of acid in vinegar. However, there is a misunderstanding regarding the interpretation of the calculated mass of acetic acid as its molar mass, which is clarified later in the discussion.

Contextual Notes

Some calculations and assumptions are presented without detailed explanations, such as the conversion of volumes to moles and the interpretation of the results. There may be additional considerations regarding the accuracy of measurements and the concentration of acetic acid in vinegar that are not fully addressed.

majinknight
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Hello this is my question. Ok I need to find the molar mass of acetic acid and then calculate the mass of acid in the volume of vinegar I used. Now the equation for the lab i did was
CH3COOH + NaOH produces NaCH3COO + H20

The information I have is that the concentration of the sodium hydroxide is 0.20 mol/L, the volume of sodium hydroxide is 79mL, the volume of acetic acid I used was 25mL, I calculated the number of moles use in the sodium hydroxide and it was 0.0158 mol and since everything is on a 1 to 1 basis the number of moles for the acetic acid is 0.0158mol. From that I calculated the number of moles of acetic acid and it is 0.632 mol/L. I calculated the molar mass of the acetic acid by taking the 0.0158 mol of CH3COOH x 60g (the weight of the acid) which got me an answer of 0.948 grams. Now what I do not understand is how to calculate the mass of acid in the volume of vinegar. I may have everything to answer the question here but i just don't know what to do.

Plz Help me!
 
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Originally posted by majinknight
Hello this is my question. Ok I need to find the molar mass of acetic acid and then calculate the mass of acid in the volume of vinegar I used. Now the equation for the lab i did was
CH3COOH + NaOH produces NaCH3COO + H20
Hi Majinknight! Welcome to the forums!

So to summarize: You neutralized 25 ml of CH3COOH with 79 ml of NaOH [0.20 mol/l]

You calculated the number of moles of CH3COOH in your solution: 79 * 0.20*10-3 = 0.0158. You do not have to calculate the concentration of the CH3COOH!

Next, you calculated molar mass of CH3COOH, you do not explain how you did that? I can do it out of my head: the molar mass of C=12, O=16, H=1. Combine that and CH3COOH = 60 grams per mole.

Without knowing it you already answered your own question: "Now what I do not understand is how to calculate the mass of acid in the volume of vinegar".

You multiplied the molar mass of CH3COOH with the number of moles in the volume and that is your answer: 0.0158 * 60 = 0.948 g.
 
Oh really the question said find the molar mass of acetic acid. Then calculate the mass of acid in the volume of vinegar. I thought that the molar mass of acetic acid was 0.948g, but the molar mass is just the 60grams. Ok Thank You so much.
 
Yes, the molar mass (mw) is the mass of a mole of a substance
 

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