CO2 and Kr Mixture: Calculating Original CO2 and Recoverable Kr Amounts

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Discussion Overview

The discussion revolves around a problem involving a mixture of carbon dioxide (CO2) and krypton (Kr), focusing on calculating the original amounts of CO2 and the recoverable amount of Kr after CO2 is removed. The context is a homework-related inquiry in general chemistry.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about how to approach the problem of calculating the amounts of CO2 and Kr.
  • Another participant suggests that the original poster should first share their thoughts or attempts at solving the problem before receiving help.
  • A third participant proposes using the concept of partial pressure ratios to determine the molar ratio, which can then be used to calculate the mass ratio and ultimately the individual masses of CO2 and Kr.

Areas of Agreement / Disagreement

The discussion does not appear to reach a consensus, as participants have differing approaches to solving the problem and the original poster has not yet provided their thoughts.

Contextual Notes

There are no specific limitations noted, but the problem requires assumptions about the behavior of gases and the application of gas laws.

Who May Find This Useful

This discussion may be useful for students studying general chemistry, particularly those interested in gas mixtures and calculations involving partial pressures.

babbagee
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A misture of CO2 and Kr weighs 35.0 g and exerts a pressure of .708 atm in its container. Since Kr is expensive, you wish to recover it from the mixture. Afterthe CO2 is completely removed by absorption with NaOH(s), the pressure in the container is .250 atm. How many grams of CO2 were originally present? How many grams of Kr can you recover?

I have no idea how to do this?
Thanks
 
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It would be of no help if we will give you logical reason at first site, which you yourself think first pls reply with whatever you have thought while attempting the problem
 
Remember that the partial pressure ratio is the molar ratio. From the molar ratio calculate the mass ratio. From the mass ratio find the individual masses of the original compounds.

It shouldn't be too difficult.

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Thanks
 

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