- #1
kajalove
- 15
- 0
hey
I'm currently learning about velocities of objects thrown horizontally.The main point is that initial horizontal speed v[0] will remain constant while vertical velocity will accelerate with a = 10m / s^2.
But when learning formulas there are few things that got me confused:
1)We can calculate net velocity of falling object moment before it hits the ground with:
h --> height
v^2 = v[0]^2 + g^2*t^2 = v[0]^2 + 2*g*h
We got g^2*t^2 = 2*g*h since t^2 = 2h / gDo we use this formula for net velocity also when an object is thrown in vertical direction with initial speed of v[0]? If that is the case then at least from my understanding this formula doesn't make much sense:
*Firstly, t^2 = 2h / g is true only when object is dropped (and its initial velocity v[0] is 0 => v^2 = v[0]^2 + 2*g*h = 2*g*h)
*If we toss objects vertically with initial speed of v[0],then its final net velocity should be :
v = v[0] + g*t,and not v=sqrt( v[0]^2 + g^2*t^2 )2)And if formula for net velocity v[0]^2 + g^2*t^2 is indeed the same no matter if object is tossed with v[0] horizontally or vertically from same height, then it would suggest net velocity in both cases is the same. Which again doesn't make much sense to me!
thank you for your help
I'm currently learning about velocities of objects thrown horizontally.The main point is that initial horizontal speed v[0] will remain constant while vertical velocity will accelerate with a = 10m / s^2.
But when learning formulas there are few things that got me confused:
1)We can calculate net velocity of falling object moment before it hits the ground with:
h --> height
v^2 = v[0]^2 + g^2*t^2 = v[0]^2 + 2*g*h
We got g^2*t^2 = 2*g*h since t^2 = 2h / gDo we use this formula for net velocity also when an object is thrown in vertical direction with initial speed of v[0]? If that is the case then at least from my understanding this formula doesn't make much sense:
*Firstly, t^2 = 2h / g is true only when object is dropped (and its initial velocity v[0] is 0 => v^2 = v[0]^2 + 2*g*h = 2*g*h)
*If we toss objects vertically with initial speed of v[0],then its final net velocity should be :
v = v[0] + g*t,and not v=sqrt( v[0]^2 + g^2*t^2 )2)And if formula for net velocity v[0]^2 + g^2*t^2 is indeed the same no matter if object is tossed with v[0] horizontally or vertically from same height, then it would suggest net velocity in both cases is the same. Which again doesn't make much sense to me!
thank you for your help