New Reply

Entrance loss from open channel to pipe

 
Share Thread Thread Tools
Feb11-06, 04:30 PM   #1
 

Entrance loss from open channel to pipe

Hi!

I have the following equation for the entrance loss from an open channel to a pipe, but I'm not sure how it was derived:

hloss = K*(V2^2 - V1^2)/2g

I have always seen entrance losses as: K*(V^2)/2g, but why is the channel flow velocity considered in the equation above.

Thanks, Michelle
PhysOrg.com
PhysOrg		 science news on PhysOrg.com

>> Bird's playlist could signal mental strengths and weaknesses
>> Minus environment, patterns still emerge: Computational study tracks E. coli cells' regulatory mechanisms
>> Bacterium uses natural 'thermometer' to trigger diarrheal disease, scientists find
Apr18-11, 10:01 AM   #2
 
I think it is because the velocity in the open channel (V1) is assumed to be zero, but I am not 100% sure.
New Reply
Thread Tools


Similar Threads for: Entrance loss from open channel to pipe
Thread Forum Replies
Transition from pipe flow to open channel flow Mechanical Engineering 6
Question on open channel flows Advanced Physics Homework 0
Heat Loss in a Hot Water Pipe System Engineering Systems & Design 35
Loss due to open channel to pipe flow transition General Engineering 3
Open pipe problem Introductory Physics Homework 2