Differentiating mult-variable equation

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SUMMARY

The discussion focuses on solving the multivariable equation \( x^3 + x \tan^{-1} y = e^y \) using implicit differentiation. The user expresses difficulty in applying both implicit differentiation and logarithmic differentiation techniques. The derived equation for the derivative \( \frac{dy}{dx} \) is \( 3x^2 + \tan^{-1} y + \frac{xy'}{1 + y^2} = ey' \), leading to the need to isolate \( y' \). The consensus is that logarithmic differentiation is unnecessary for this problem.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with logarithmic differentiation
  • Knowledge of trigonometric functions, specifically \( \tan^{-1} y \)
  • Basic calculus concepts, including derivatives and their applications
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  • Practice implicit differentiation with various multivariable equations
  • Explore the applications of logarithmic differentiation in complex functions
  • Study the properties and derivatives of inverse trigonometric functions
  • Learn techniques for isolating variables in derivative equations
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Students and educators in calculus, mathematicians dealing with multivariable functions, and anyone looking to enhance their skills in differentiation techniques.

dbrag
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Any ideas for solving this, I am having trouble using implicit differentiation along with using log differentiation, thanx!:

x^3 + x tan^-1 y = e^y
 
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Differentiate w.r.t x

[tex]\frac{df(y)}{dx}=\frac{df(y)}{dy}\frac{dy}{dx}[/tex]
 
In other words, the derivative of y with respect to x is:


3x2+ tan-1y+ xy'/(1+ y2)= eyy'. Now solve for y'.

I see no reason to use "logarithmic differentiation".
 

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