Changing X-Polarized Light to Y-Polarization with Lossless Polarizers

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Homework Help Overview

The discussion revolves around the process of converting x-polarized light to y-polarized light using lossless polarizers. Participants are examining the implications of polarizer angles and intensity loss in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of two polarizers at specific angles to achieve the desired polarization change. Questions arise regarding the definition of angles and the intensity loss associated with each polarizer.

Discussion Status

There is a general agreement on the approach of using two polarizers, though some participants question the intensity calculations and definitions of angles. Productive dialogue is occurring around the setup and assumptions involved.

Contextual Notes

Participants are considering the impact of angle definitions on the effectiveness of the polarizers and the resulting intensity of the light. The discussion includes references to specific angles and their relationship to the x and y polarization directions.

UrbanXrisis
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change x-polarized light to y-polarized light by suing lossless polarizers

Using [tex]I_{pol}=Icos^2 \theta[/tex] I would first use a polarizer with theta=45 to change x polarized light 45 degrees without losing intenisity. Then I wil using a polarizer with theta=135 to change the polarized light y-polarization without losing intensity. is this the correct way of approching this problem?
 
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The idea is good (I think, but I don't know how you define your angles theta). If the polarization direction of the polarizer is at some nonzero angle wrt the polarization direction of the light you always have some loss of intensity, since the E-field component of the light-wave perpendicular to the polarization direction of the polarizer is blocked out.
 
say the light is polarized vertically like this:


| | | | | |

then the polarizers that are like this:

\ \ \ \ \

putting the two together, the angle is between the two like this:

\|


would what I did still be corrent according to this definition of theta?
 
I think what you did is correct, but I would have called the two polarizer angles 45 degrees and 90 degrees. The x-polarization direction is at zero degrees, and the final y-polarization direction is at 90 degrees.
 
Yes, the setup will give you linearly polarized light in the y-direction. But the intensity is not [itex]I_0\cos(\theta)[/itex].
The light intensity drops twice. Once after the first polarizer and again after the second.
 
would a 45 degree (wrt x-axis) polarizer and then a 90 degree (wrt x-axis) polarizer work? since, it it would be...

I'=I cos(45)^2

which would lead to I'/2 (this is polarized 45 degree to x axis)

and then applying the 90 degree (wrt the x axis) polarizer, which makes a 45 degree angle to the light:

I''=I/2 cos(45)^2
I''=I/4, which is 90 degrees wrt to the x, which makes it y polarized

does this work?
 
Yes, that would work as you describe.
 

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