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Implicit Differentiation  Second Derivative 
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#1
Apr106, 10:52 PM

P: 97

Were assigned questions regarding implicit differentiation and the second derivative but did not receive a formal lesson so I need some explanations.
Example: Find the second derivative x^3 + y^3 = 1 I found this solution on the internet and the answer matches the one in the textbook. However, I don't understand how 2xy^3  2x^4/y^5 turned into just 2xy^3/y^5 (This is the 56 step). Furthermore, I don't see how 2xy^3/y^5 equals 2x(y^3 + x^3)/y^5 (67 step). Simply, I need explanations for this solutions rationale. Thanks. 


#2
Apr106, 11:30 PM

Sci Advisor
HW Helper
P: 2,954

At the very end they use x^3+y^3=1, which was the initial equation. 


#3
Apr106, 11:50 PM

P: 97

Ahhh, now I see it, thanks for pointing that out!



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