|May3-06, 02:24 PM||#1|
Can someone check my work please I'm pretty sure I don't have the right answer but I can't figure out what I have wrong.
The question is:
A simple harmonic oscillator has total energy E=1/2kA^2
where A is the amplitude of oscillation.
For what value of the displacement does the kinetic energy equal the potential energy?
So I figure that if KE is equal to PE, then PE=1/2E
kx^2 = 1/2kA^2
x = 1/4A
|May3-06, 02:59 PM||#3|
I think I see my error.
Is the answer x = 0.71A ?
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