## harmonic oscillator

Can someone check my work please I'm pretty sure I don't have the right answer but I can't figure out what I have wrong.

The question is:
A simple harmonic oscillator has total energy E=1/2kA^2
where A is the amplitude of oscillation.
For what value of the displacement does the kinetic energy equal the potential energy?

So I figure that if KE is equal to PE, then PE=1/2E

Therefore:

1/2kx^2 =1/2(1/2kA^2)
kx^2 = 1/2kA^2
x = 1/4A

Any ideas?
 PhysOrg.com science news on PhysOrg.com >> King Richard III found in 'untidy lozenge-shaped grave'>> Google Drive sports new view and scan enhancements>> Researcher admits mistakes in stem cell study

Mentor
Blog Entries: 1
 Quote by flower76 So I figure that if KE is equal to PE, then PE=1/2E
Good.

 Therefore: 1/2kx^2 =1/2(1/2kA^2)
Good.
 kx^2 = 1/2kA^2
Good.
 x = 1/4A
Not good.
 I think I see my error. Is the answer x = 0.71A ?

Mentor
Blog Entries: 1

## harmonic oscillator

Yep. $x = (1/\sqrt{2}) A$