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Harmonic oscillator 
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#1
May306, 02:24 PM

P: 51

Can someone check my work please I'm pretty sure I don't have the right answer but I can't figure out what I have wrong.
The question is: A simple harmonic oscillator has total energy E=1/2kA^2 where A is the amplitude of oscillation. For what value of the displacement does the kinetic energy equal the potential energy? So I figure that if KE is equal to PE, then PE=1/2E Therefore: 1/2kx^2 =1/2(1/2kA^2) kx^2 = 1/2kA^2 x = 1/4A Any ideas? 


#3
May306, 02:59 PM

P: 51

I think I see my error.
Is the answer x = 0.71A ? 


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